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i386: Fixed setting of IF flag when interrupts are triggered in virtual 8086 mode. (no whatsnew)

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mahlemiut 2012-01-12 08:11:18 +00:00
parent 5f6f7b8267
commit a771e136c6
1 changed files with 2 additions and 2 deletions
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4
src/emu/cpu/i386/i386.c
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@ -613,7 +613,7 @@ static void i386_trap(i386_state *cpustate,int irq, int irq_gate, int trap_level
tempflags = get_flags(cpustate); tempflags = get_flags(cpustate);
cpustate->VM = 0; cpustate->VM = 0;
cpustate->TF = 0; cpustate->TF = 0;
if(irq_gate == 1) if(type == 0x0e || type == 0x06)
cpustate->IF = 0; cpustate->IF = 0;
tempSS = cpustate->sreg[SS].selector; tempSS = cpustate->sreg[SS].selector;
tempESP = REG32(ESP); tempESP = REG32(ESP);
@ -2241,7 +2241,7 @@ static void i386_protected_mode_iret(i386_state* cpustate, int operand32)
//SSDPL = (stack.flags >> 5) & 0x03; //SSDPL = (stack.flags >> 5) & 0x03;
/* Return to v86 mode */ /* Return to v86 mode */
popmessage("IRET (%08x): Returning to Virtual 8086 mode.",cpustate->pc); logerror("IRET (%08x): Returning to Virtual 8086 mode.\n",cpustate->pc);
// Should these be done at this point? The 386 programmers' reference is a bit confusing about this // Should these be done at this point? The 386 programmers' reference is a bit confusing about this
/* if(RPL != 3) /* if(RPL != 3)
{ {